Brain Teaser

Discussion in 'REME' started by RCEME, May 5, 2010.

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  1. First person to answer the following (showing working) wins a NAAFI pie:

    How many soldiers are there in a group of 27 sailors and soldiers if there are four fifths as many sailors as soldiers?

    (A) 6
    (B) 15
    (C) 21
    (D) 22


    :)

    No, I'm not sat in the Kremlin on a Level 1 Maths resit! This is one of the enlistment apptitude questions for the Canadian Forces (CF) and most of the people I work with couldn't even do it.

    8O
     
  2. non of the above, The answer is 12
     
  3. go on then...
    4/5 = sailors as a fraction of group.
    therefore, for every 5 soldiers, there will be 4 sailors.
    27 in group, which splits to 3 lots of [4 sailors] and [5 soldiers]. (working= 4+5 =9 ---> 27/9=3)

    4(sailors) * 3 = 12 sailors in total.
    5(soldiers) * 3 = 15 soldiers in total.

    Answer B.
     
  4. Well done that man!
    Quick calculation: 4 fifths plus 5 fifths (as in 4 fifths of the OTHER half) = 9; 27/9 = 3; 4 x 3 = 12. Looks like the guy who sat the test couldn't even do it!
     
  5. RTFQ!
     
  6. 4/5 the quantity of soldiers are sailors.

    100 soldiers would mean 80 sailors etc ( just to explain the math)

    We know that for every 5 soldiers there are 4 sailors

    5 + 4 = 9
    5 + 4 = 9
    5 + 4 = 9

    15 soldiers + 12 sailors = 27 service persons

    B
     
  7. where's my NAAFI pie?
     
  8. Fugly

    Fugly LE DirtyBAT

    4/5 sailors to soldiers. 9 men.

    27/9 = 3 groups.

    3*4 sailors = 12 sailors
    3*5 soldiers = 15 soldiers.

    B.
     
  9. Fugly

    Fugly LE DirtyBAT

    I had it away while you were laughing at the other two above who got it wrong.
     
  10. cunttttttt!
     
  11. Has anyone got a passback?
     
  12. Fugly

    Fugly LE DirtyBAT

    The answer wasn't up there when I started typing, but I'm using my extra wide head dobber and I couldn't find my programmable calculator. I had to ask the cleaner in the end.
     
  13. Nice one fella, completely wrong. :p

    I thought I'd chuck in some algebra just to prove the 18-months wasn't wasted:

    Being an obvious fan of meat filled pastries, I will use the analogy of pies.

    The complete group (soldiers) is a whole pie (P). This means that the incomplete group is 4/5 of P. Both added both together make 27, therefore the simple algebraic equation is:

    P + 4P = 27
    5

    We now multiply the whole equation by 5 to get rid of the fractions:

    5P + 20P = 135
    5

    This cancels down to: 5P + 4P = 135

    Therefore: 9P = 135

    Therefore: P = 15

    As P = Soldiers, there are 15 soldiers in the group.
     
  14. Wouldn't it be simpler to just separate those wearing DPM from those wearing dark blue and then count them ?
     
  15. Fugly

    Fugly LE DirtyBAT

    [pedant]

    After multiplying by 5, you didn't remove the denominator of 5. Marks deducted.

    :D

    [/pedant]